Covalent and Coordinate Bonding

AS · 19 min

When two non-metal atoms bond, neither can pull an electron completely away from the other, so instead they share electrons. This note defines covalent bonding in the syllabus wording, shows how to draw dot-and-cross diagrams for every molecule the syllabus names (including multiple bonds, expanded octets and odd-electron species), explains coordinate (dative covalent) bonding in the ammonium ion and in AlX2ClX6\ce{Al2Cl6}, and defines bond energy and bond length so you can use them to compare how reactive molecules are. Dot-and-cross diagrams and the two bond definitions appear in Paper 2 almost every series.

What a covalent bond is

Think of two hydrogen atoms approaching each other. Each nucleus attracts its own electron, but also the other atom's electron. When the atoms are close enough, the two electrons settle in the region between the nuclei, where both nuclei attract them. The shared pair acts like glue: each positive nucleus is attracted to the negative pair sitting between them.

Definition

Covalent bonding is the electrostatic attraction between the nuclei of two atoms and a shared pair of electrons.

Three points follow from this definition.

  • The bond is electrostatic, just like ionic and metallic bonding. What differs is what is attracted to what: here, two nuclei to one shared pair.
  • A single bond is one shared pair, a double bond two shared pairs and a triple bond three shared pairs.
  • A covalent bond is directional: it points from one nucleus to the other. That is why covalent molecules have definite shapes, unlike ionic lattices.

Covalent bonds form between atoms whose electronegativities are similar, usually two non-metals. When the electronegativities are equal (as in ClX2\ce{Cl2}) the pair is shared equally; when they differ (as in HCl\ce{HCl}) the pair is pulled towards the more electronegative atom and the bond is polar. You will use bond polarity in the note on intermolecular forces.

Lone pairs and bonding pairs

The outer-shell electrons of a covalently bonded atom are in two kinds of pair:

  • a bonding pair is shared between two atoms;
  • a lone pair (non-bonding pair) belongs to one atom only.

In ammonia, nitrogen has three bonding pairs (one to each hydrogen) and one lone pair. Counting these pairs is the key to working out molecular shapes in the next notes.

Dot-and-cross diagrams for molecules

A dot-and-cross diagram for a molecule shows the outer-shell electrons of each atom. Electrons that came from one atom are drawn as dots, electrons from the other atom as crosses, and shared pairs sit where the atoms' circles overlap.

Method

Drawing a dot-and-cross diagram for a molecule

  1. Write the number of outer-shell electrons of each atom (its group number for Groups 1, 2 and 13 to 17).
  2. Decide which atom is central (usually the one that forms the most bonds, and never hydrogen).
  3. Pair up one electron from the central atom with one from each outer atom to make a bonding pair. Add double or triple bonds if an atom still needs electrons.
  4. Place the remaining electrons on each atom as lone pairs.
  5. Check: hydrogen has 2 electrons; most other atoms have 8 (the octet); count electrons for any atom that might be an exception (see below).

The diagrams below cover the molecules the syllabus names. Circles are optional in an exam (you may draw the atoms' symbols with electrons around them), but shared pairs must be clearly between the two atoms and every outer electron must be shown.

Cl Cl
Dot-and-cross diagram for chlorine, Cl2. One shared pair (one dot, one cross) in the overlap; each atom keeps three lone pairs.
O H H
Water, H2O: two bonding pairs and two lone pairs on oxygen.
N H H H
Ammonia, NH3: three bonding pairs and one lone pair on nitrogen.
C H H H H
Methane, CH4: four bonding pairs around carbon and no lone pairs.

Hydrogen chloride looks like chlorine but with one of the chlorine atoms replaced by a hydrogen with no lone pairs: one shared pair, and three lone pairs on chlorine. Hydrogen, HX2\ce{H2}, is simply two overlapping circles with one dot and one cross between them.

Multiple bonds

When an atom still has too few electrons after forming single bonds, it shares a second or third pair with the same neighbour.

O O
Oxygen, O2: a double bond (two shared pairs) and two lone pairs on each atom.
C O O
Carbon dioxide, CO2: two double bonds (two shared pairs each); each oxygen keeps two lone pairs.
N N
Nitrogen, N2: a triple bond (three shared pairs) and one lone pair on each atom.

For the two hydrocarbons in the list:

moleculebonding pairslone pairskey feature
ethane, CX2HX6\ce{C2H6}7 (one C–C, six C–H)0every carbon has four single bonds
ethene, CX2HX4\ce{C2H4}6 (two shared between the carbons, four C–H)0a C=C\ce{C=C} double bond: four electrons, two dots and two crosses, between the carbons
Key result
moleculebondslone pairs on each atom
HX2\ce{H2}one single bondnone
ClX2\ce{Cl2}, HCl\ce{HCl}one single bondthree on each Cl
OX2\ce{O2}one double bondtwo on each O
NX2\ce{N2}one triple bondone on each N
COX2\ce{CO2}two double bondsnone on C, two on each O
NHX3\ce{NH3}three single bondsone on N
CHX4\ce{CH4}four single bondsnone
CX2HX6\ce{C2H6}seven single bondsnone
CX2HX4\ce{C2H4}one double bond, four single bondsnone

Exceptions to the octet rule

Most atoms in molecules have eight outer electrons, but the syllabus expects you to know three kinds of exception.

Expanded octets in Period 3

Elements in Period 3 and beyond can have more than eight electrons in their outer shell. Their outer shell is the third shell, which contains empty 3d orbitals of fairly similar energy to the 3s and 3p orbitals. Electrons can be promoted into these, so more electrons are available to pair up in bonds. Period 2 elements (such as nitrogen and oxygen) cannot do this: their second shell has no d sub-shell, so it holds at most eight electrons.

moleculecentral atom's outer electronselectrons around central atomarrangement
SOX2\ce{SO2}S: 610two S=O\ce{S=O} double bonds and one lone pair
PClX5\ce{PCl5}P: 510five P–Cl single bonds, no lone pairs
SFX6\ce{SF6}S: 612six S–F single bonds, no lone pairs
S O O
Sulfur dioxide, SO2, drawn with two S=O double bonds. Sulfur has 10 electrons in its outer shell (four bonding pairs and one lone pair): an expanded octet.

In PClX5\ce{PCl5}, all five of phosphorus's outer electrons are paired with one electron from each of five chlorine atoms; each chlorine keeps three lone pairs. In SFX6\ce{SF6}, all six of sulfur's outer electrons pair with one electron from each of six fluorine atoms.

Electron-deficient molecules

Some central atoms have fewer than eight electrons. Boron has three outer electrons, so in BFX3\ce{BF3} it forms three single bonds and has only six electrons around it. Aluminium chloride, AlClX3\ce{AlCl3}, is the same: aluminium has six electrons. These molecules can accept a lone pair from another species, which leads to coordinate bonding below.

Odd-electron species

A molecule with an odd total number of outer electrons cannot have every electron paired. Nitrogen monoxide, NO\ce{NO}, has 5+6=115 + 6 = 11 outer electrons. Drawn with an N=O\ce{N=O} double bond, oxygen has two lone pairs (8 electrons) but nitrogen has one lone pair and one unpaired electron, so only 7 electrons. Nitrogen dioxide, NOX2\ce{NO2}, is also an odd-electron molecule (5+6+6=175 + 6 + 6 = 17). Species with an unpaired electron are called radicals, and they are typically very reactive, which you will meet again in organic chemistry.

Coordinate (dative covalent) bonding

In an ordinary covalent bond, each atom provides one electron of the shared pair. In a coordinate bond, also called a dative covalent bond, both electrons of the shared pair come from the same atom.

Definition

A coordinate (dative covalent) bond is a covalent bond in which both electrons of the shared pair are provided by one of the bonding atoms.

Two conditions are needed:

  1. one atom has a lone pair to donate;
  2. the other atom has an empty orbital in its outer shell that can accept the pair (it is electron deficient).

A coordinate bond is drawn as an arrow from the donor atom to the acceptor atom, for example HX3N→HX+\ce{H3N -> H+}. Once formed, a coordinate bond is identical to any other covalent bond of the same type: the four N–H bonds in the ammonium ion are indistinguishable.

The ammonium ion

When ammonia gas and hydrogen chloride gas meet, white fumes of ammonium chloride form:

NHX3(g)+HCl(g)→NHX4Cl(s)\ce{NH3(g) + HCl(g) -> NH4Cl(s)}

The hydrogen chloride transfers HX+\ce{H+} to ammonia. The HX+\ce{H+} ion has no electrons at all, so it has an empty 1s orbital. The nitrogen lone pair is donated into it, forming a coordinate bond and the ammonium ion, NHX4X+\ce{NH4+}. The chloride ion keeps the electron from the original H–Cl bond, so ammonium chloride is an ionic compound made of NHX4X+\ce{NH4+} and ClX−\ce{Cl-} ions.

N H H H H +
Ammonium ion, NH4+. The top N–H bond is the coordinate bond: both of its electrons (two dots) came from the lone pair on nitrogen.

The same thing happens when an acid dissolves in water: a lone pair on the oxygen of water forms a coordinate bond to HX+\ce{H+}, giving the oxonium ion, HX3OX+\ce{H3O+}.

Aluminium chloride and Al2Cl6

At about 180 ∘C180\ ^\circ\text{C} aluminium chloride sublimes, and in the vapour (and in the solid at lower temperature) it exists largely as dimers, AlX2ClX6\ce{Al2Cl6}:

2 AlClX3⇌AlX2ClX6\ce{2AlCl3 <=> Al2Cl6}

In AlClX3\ce{AlCl3} the aluminium has only six outer electrons and an empty orbital. A chlorine atom on one AlClX3\ce{AlCl3} unit has three lone pairs. One lone pair from a chlorine on each AlClX3\ce{AlCl3} unit is donated to the aluminium of the other unit, so the dimer contains two coordinate bonds. The two "bridging" chlorine atoms each bond to both aluminium atoms; the other four chlorines are "terminal".

After dimerisation, each aluminium atom has four bonding pairs (three ordinary covalent bonds and one coordinate bond), so it has eight electrons: a full octet. The arrangement around each aluminium is roughly tetrahedral.

feature of AlX2ClX6\ce{Al2Cl6}detail
total Al–Cl bonds8
coordinate bonds2 (from bridging Cl to Al)
electrons around each Al8
lone pairs on each bridging Cl2
lone pairs on each terminal Cl3
Watch out

In a dot-and-cross diagram for a coordinate bond, both electrons of the shared pair must be the same symbol (both dots or both crosses), and they must be the symbol of the donor atom. In NHX4X+\ce{NH4+} the coordinate bond has two of nitrogen's electrons; the hydrogen that came in as HX+\ce{H+} contributes none. Students lose the mark by drawing a dot and a cross in every N–H bond.

Bond energy and bond length

How strong is a covalent bond, and how does that relate to reactivity? Two measurable quantities answer this.

Definition

Bond energy is the energy required to break one mole of a particular covalent bond in the gaseous state.

Bond length is the internuclear distance of two covalently bonded atoms.

Bond energies are always positive, because breaking a bond always needs energy. The phrase "in the gaseous state" matters: breaking bonds in a liquid or solid would also involve overcoming intermolecular forces.

For a diatomic molecule, the bond energy is exact: there is only one bond to break. For a bond such as C–H, the energy needed depends slightly on the molecule it is in, so the data booklet quotes an average bond energy over many compounds. You will use this distinction in the note on bond energies and enthalpy changes.

How bond length and bond energy are linked

The more electrons shared between two nuclei, the more strongly the nuclei are attracted to the pairs and the closer they are pulled together. So, for the same pair of atoms, multiple bonds are shorter and stronger:

bondbond energy / kJ mol⁻¹bond length / nm
C–C3500.154
C=C6100.134
C≡C8400.120

Down a group, atoms get larger, the bonding pair is further from the nuclei and more shielded, so the attraction is weaker. Bonds get longer and weaker:

bondbond energy / kJ mol⁻¹bond length / nm
H–F5620.092
H–Cl4310.127
H–Br3660.141
H–I2990.161

Bond energy and reactivity

Most reactions start by breaking a bond. A molecule with only strong bonds is hard to break apart, so it tends to be unreactive; a molecule with a weak bond reacts more readily.

  • Nitrogen, NX2\ce{N2}, has a triple bond with bond energy 944 kJ mol−1944\ \text{kJ mol}^{-1}, among the strongest known. That is why nitrogen is so unreactive and makes up most of the atmosphere, and why the Haber process needs a catalyst, high temperature and high pressure.
  • Hydrogen halides: thermal stability decreases from HF to HI because the H–X bond gets longer and weaker. A hot wire plunged into hydrogen iodide produces violet iodine vapour; hydrogen chloride is unaffected.
  • Halogenoalkanes (organic chemistry): the C–I bond is the longest and weakest carbon–halogen bond, so iodoalkanes react fastest in substitution reactions.
Tip

Bond polarity can also affect reactivity, but at AS, when a question gives bond energies and asks you to compare reactivity, the expected answer is about bond strength: weaker (longer) bond, less energy needed to break it, more reactive.

Worked examples

Counting electrons in a molecule

Draw a dot-and-cross diagram (or describe one fully) for hydrogen cyanide, HCN\ce{HCN}, in which carbon is the central atom. State the number of bonding pairs and lone pairs.

Solution

Outer electrons: H 1, C 4, N 5.

Carbon forms one single bond to H (one dot, one cross). Carbon still has three electrons to share, so it forms a triple bond with nitrogen: three shared pairs, each with one electron from C and one from N. Nitrogen has used three of its five electrons, so it keeps one lone pair.

Check: H has 2 electrons; C has 2+6=82 + 6 = 8; N has 6+2=86 + 2 = 8.

So there are 4 bonding pairs (one C–H, three C≡N) and 1 lone pair (on N).

Expanded octet

Phosphorus forms both PClX3\ce{PCl3} and PClX5\ce{PCl5}, but nitrogen forms only NClX3\ce{NCl3}. Explain this difference.

Solution

Phosphorus and nitrogen both have five outer electrons. In PClX3\ce{PCl3} and NClX3\ce{NCl3}, three of these form bonds and two remain as a lone pair, giving an octet.

To form five bonds, the central atom must have ten electrons in its outer shell. Phosphorus is in Period 3: its outer shell is the third shell, which has empty 3d orbitals available, so it can expand its octet and use all five electrons in bonds. Nitrogen is in Period 2: its outer shell (the second shell) has only 2s and 2p orbitals and can hold a maximum of eight electrons, so it cannot form five bonds.

Coordinate bonding

Boron trifluoride, BFX3\ce{BF3}, reacts with ammonia to form the compound HX3NBFX3\ce{H3NBF3}.

(a) Explain why BFX3\ce{BF3} and NHX3\ce{NH3} can form a bond. (b) Describe the bond formed. (c) State the number of electrons around boron before and after the reaction.

Solution

(a) Nitrogen in NHX3\ce{NH3} has a lone pair. Boron in BFX3\ce{BF3} has only six outer electrons and so has an empty orbital that can accept a pair.

(b) A coordinate (dative covalent) bond: the nitrogen donates its lone pair into the empty orbital of boron, so both electrons of the shared pair come from nitrogen. It is shown as HX3N→BFX3\ce{H3N -> BF3}.

(c) Before: 6 electrons around boron. After: 8 electrons (three B–F bonding pairs and the N→B pair).

Bond energy and reactivity

The bond energies of the halogens are: Cl–Cl 242242, Br–Br 193193, I–I 151 kJ mol−1151\ \text{kJ mol}^{-1}. The bond energies of the hydrogen halides are: H–Cl 431431, H–Br 366366, H–I 299 kJ mol−1299\ \text{kJ mol}^{-1}.

(a) Explain the trend in the H–X bond energies. (b) Predict and explain which hydrogen halide decomposes most readily on heating.

Solution

(a) Down Group 17 the halogen atom gets larger. The H–X bond gets longer, so the bonding pair is further from the halogen nucleus and more shielded by inner electrons. The attraction between the nuclei and the shared pair is weaker, so less energy is needed to break the bond.

(b) Hydrogen iodide. Its H–I bond is the longest and weakest (299 kJ mol−1299\ \text{kJ mol}^{-1}), so the least energy is needed to break it: 2 HI(g)→HX2(g)+IX2(g)\ce{2HI(g) -> H2(g) + I2(g)}. Violet iodine vapour is seen.

Exam-hard: aluminium chloride

Aluminium chloride exists as AlX2ClX6\ce{Al2Cl6} molecules in the vapour at 190 ∘C190\ ^\circ\text{C} but as AlClX3\ce{AlCl3} molecules at 800 ∘C800\ ^\circ\text{C}.

(a) Describe the bonding in AlX2ClX6\ce{Al2Cl6}, identifying every type of bond. (b) Give the total number of electrons in the outer shell of each aluminium atom in AlClX3\ce{AlCl3} and in AlX2ClX6\ce{Al2Cl6}. (c) Suggest why the dimer breaks up at high temperature.

Solution

(a) Each aluminium atom forms three ordinary covalent bonds to chlorine atoms (one electron from Al, one from Cl in each). In addition, one chlorine atom on each AlClX3\ce{AlCl3} unit uses one of its lone pairs to form a coordinate (dative covalent) bond to the aluminium atom of the other unit. So AlX2ClX6\ce{Al2Cl6} has six covalent Al–Cl bonds and two coordinate Al–Cl bonds; the two bridging chlorines each bond to both aluminium atoms.

(b) AlClX3\ce{AlCl3}: 6 electrons (three bonding pairs). AlX2ClX6\ce{Al2Cl6}: 8 electrons (three bonding pairs plus the coordinate pair).

(c) Breaking the dimer into two AlClX3\ce{AlCl3} molecules means breaking the two coordinate bonds, which needs energy: AlX2ClX6→2 AlClX3\ce{Al2Cl6 -> 2AlCl3} is endothermic. At high temperature the molecules collide with enough energy to break these bonds, and the bridging Al–Cl bonds are longer and weaker than the terminal ones, so the dimer splits up while the terminal bonds stay intact.

Watch out
  • Forgetting lone pairs. A dot-and-cross diagram must show all outer-shell electrons, including every lone pair on chlorine, oxygen or nitrogen. A diagram of HCl\ce{HCl} with only the shared pair scores zero.
  • Inventing an octet for an expanded-octet atom. SFX6\ce{SF6} has 12 electrons around sulfur, not 8. Count, do not assume.
  • Confusing bond energy with enthalpy change of atomisation. Bond energy refers to one mole of bonds in the gaseous state, not one mole of atoms formed.
  • Saying a molecule is unreactive because it is "stable". Give the reason: the bond is strong (high bond energy), so a lot of energy is needed to break it.
Exam tip
  • Learn the definitions word for word. Covalent bonding: "electrostatic attraction between the nuclei of two atoms and a shared pair of electrons". Bond energy: "energy required to break one mole of a particular covalent bond in the gaseous state". Bond length: "internuclear distance of two covalently bonded atoms".
  • "Draw a dot-and-cross diagram" means outer electrons only, with different symbols for electrons from different atoms. Mark schemes usually award one mark for the bonding pairs and one for the correct lone pairs.
  • When a question says "including the coordinate bond", make the dative pair the donor's symbol and label it.
  • For "explain why X is less reactive than Y" with bond energies given: quote the two values, say which bond is stronger, and link it to the energy needed to break the bond.
Summary
  • Covalent bond: electrostatic attraction between the nuclei of two atoms and a shared pair of electrons. Single, double and triple bonds share one, two and three pairs.
  • Dot-and-cross diagrams show all outer-shell electrons: bonding pairs in the overlap, lone pairs on the atom.
  • Know diagrams for HX2\ce{H2}, OX2\ce{O2}, NX2\ce{N2}, ClX2\ce{Cl2}, HCl\ce{HCl}, COX2\ce{CO2}, NHX3\ce{NH3}, CHX4\ce{CH4}, CX2HX6\ce{C2H6}, CX2HX4\ce{C2H4}.
  • Period 3 elements can expand their octet (empty 3d orbitals): SOX2\ce{SO2} (10), PClX5\ce{PCl5} (10), SFX6\ce{SF6} (12). BFX3\ce{BF3} and AlClX3\ce{AlCl3} are electron deficient (6). NO\ce{NO} and NOX2\ce{NO2} have an unpaired electron.
  • Coordinate bond: both electrons of the shared pair from one atom; needs a lone pair on the donor and an empty orbital on the acceptor. Examples: NHX4X+\ce{NH4+}, HX3OX+\ce{H3O+}, AlX2ClX6\ce{Al2Cl6} (two coordinate bonds).
  • Bond energy: energy to break one mole of a particular covalent bond in the gaseous state; exact for diatomics, averages otherwise.
  • Shorter bonds are stronger; weaker bonds make molecules more reactive (NX2\ce{N2} is inert because N≡N\ce{N#N} is very strong).

Practice

Question
  1. Define covalent bonding.
  2. Draw (or describe fully) the dot-and-cross diagram of ethene, CX2HX4\ce{C2H4}.
  3. State the number of bonding pairs and lone pairs around the central atom in (a) HX2O\ce{H2O}, (b) PClX5\ce{PCl5}, (c) SOX2\ce{SO2}, (d) BFX3\ce{BF3}.
  4. Describe how the ammonium ion forms when ammonia reacts with hydrogen chloride, and explain why all four N–H bonds in NHX4X+\ce{NH4+} are identical.
  5. Define bond energy and explain why bond energies are always positive.
  6. The bond energy of N≡N\ce{N#N} is 944 kJ mol−1944\ \text{kJ mol}^{-1} and that of F−F\ce{F-F} is 158 kJ mol−1158\ \text{kJ mol}^{-1}. Use these values to explain the difference in reactivity of nitrogen and fluorine.
  7. Draw (or describe) a dot-and-cross diagram for the hydroxide ion, OHX−\ce{OH-}, showing where the extra electron came from.
  8. Explain why oxygen can form only two bonds in HX2O\ce{H2O}, but sulfur can form six bonds in SFX6\ce{SF6}.
  9. Carbon monoxide, CO\ce{CO}, contains a triple bond in which one of the three shared pairs is a coordinate bond. Describe the bonding, stating which atom donates the coordinate pair and the number of lone pairs on each atom.
  10. When aluminium chloride is dissolved in an inert solvent, a molecule with formula AlX2ClX6\ce{Al2Cl6} is detected. Explain the formation of this molecule and state the total number of lone pairs in it.
Answers
  1. The electrostatic attraction between the nuclei of two atoms and a shared pair of electrons.
  2. Each carbon forms single bonds to two hydrogens (one dot, one cross each) and a double bond to the other carbon (two dots and two crosses between the carbons). No lone pairs. Each carbon has 8 outer electrons; each hydrogen has 2.
  3. (a) HX2O\ce{H2O}: 2 bonding pairs, 2 lone pairs. (b) PClX5\ce{PCl5}: 5 bonding pairs, 0 lone pairs. (c) SOX2\ce{SO2}: 4 bonding pairs (two double bonds), 1 lone pair. (d) BFX3\ce{BF3}: 3 bonding pairs, 0 lone pairs.
  4. HCl\ce{HCl} transfers HX+\ce{H+} to ammonia. The lone pair on nitrogen is donated into the empty 1s orbital of HX+\ce{H+}, forming a coordinate (dative covalent) bond: NHX3+HX+→NHX4X+\ce{NH3 + H+ -> NH4+}. Once formed, the coordinate bond is a shared pair between N and H exactly like the other three, so all four bonds have the same length and strength.
  5. The energy required to break one mole of a particular covalent bond in the gaseous state. Breaking a bond means separating the nuclei from the shared pair against their electrostatic attraction, which always requires energy (endothermic, positive).
  6. The N≡N\ce{N#N} triple bond is very strong, so a large amount of energy is needed to break it before nitrogen can react: nitrogen is very unreactive. The F–F bond is very weak, so it breaks easily and fluorine is extremely reactive.
  7. Oxygen (6 outer electrons, dots) shares one pair with hydrogen (one dot, one cross from H). Oxygen has three lone pairs, one of which contains the extra electron gained to make the ion (shown with a different symbol, for example a triangle or open circle). The whole ion is drawn in square brackets with a −- charge.
  8. Oxygen is in Period 2. It has six outer electrons and needs two more to complete an octet; its second shell cannot hold more than eight electrons, so it forms two bonds and keeps two lone pairs. Sulfur is in Period 3 and has empty 3d orbitals in its outer shell, so it can expand its octet: all six outer electrons can be used to form six bonds, giving 12 electrons around sulfur.
  9. Two of the shared pairs are ordinary covalent bonds (one electron from C and one from O in each). The third is a coordinate bond in which oxygen donates a lone pair to carbon. Carbon then has 6 electrons in bonds plus one lone pair (8); oxygen has 6 electrons in bonds plus one lone pair (8). Each atom has one lone pair.
  10. In AlClX3\ce{AlCl3} the aluminium atom has only six outer electrons and so has an empty orbital. A lone pair on a chlorine atom of one AlClX3\ce{AlCl3} molecule is donated into the empty orbital of aluminium in a second molecule, and vice versa, forming two coordinate bonds. Lone pairs: four terminal chlorines with three each (4×3=124 \times 3 = 12) and two bridging chlorines with two each (2×2=42 \times 2 = 4), so 16 lone pairs in total.

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