Brønsted–Lowry Acids and Bases

AS · 12 min

Acids and bases are among the most familiar substances in chemistry, but what actually makes something an acid? The Brønsted–Lowry theory answers in one line: acids give away protons and bases accept them. This note covers the common acids and alkalis you must know by name and formula, the Brønsted–Lowry definitions and conjugate pairs, the difference between strong and weak acids and bases (and how to tell them apart experimentally), the pH scale, and neutralisation and salt formation. It underpins the titration curves in the next note and all of the acid–base chemistry in A Level.

Common acids and alkalis

Key result
acidformulastrong or weak
hydrochloric acidHCl\ce{HCl}strong
sulfuric acidHX2SOX4\ce{H2SO4}strong
nitric acidHNOX3\ce{HNO3}strong
ethanoic acidCHX3COOH\ce{CH3COOH}weak
alkaliformulastrong or weak
sodium hydroxideNaOH\ce{NaOH}strong
potassium hydroxideKOH\ce{KOH}strong
ammonia (aqueous)NHX3\ce{NH3}weak

An alkali is a base that dissolves in water to give hydroxide ions, OHX−(aq)\ce{OH-(aq)}. All alkalis are bases, but not all bases are alkalis: copper(II) oxide is a base (it neutralises acids) but is insoluble in water, so it is not an alkali.

The Brønsted–Lowry theory

Definition

A Brønsted–Lowry acid is a proton donor.

A Brønsted–Lowry base is a proton acceptor.

A "proton" here means a hydrogen ion, HX+\ce{H+}: a hydrogen atom that has lost its only electron is just a proton.

When hydrogen chloride dissolves in water, it donates a proton to a water molecule:

HCl(g)+HX2O(l)→HX3OX+(aq)+ClX−(aq)\ce{HCl(g) + H2O(l) -> H3O+(aq) + Cl-(aq)}

HCl is the acid (proton donor) and water is the base (proton acceptor). The oxonium ion, HX3OX+\ce{H3O+}, is what is really present in acidic solutions; HX+(aq)\ce{H+(aq)} is shorthand for it. The water's oxygen uses a lone pair to form a coordinate bond to the proton.

When ammonia dissolves in water, the roles are reversed:

NHX3(aq)+HX2O(l)⇌NHX4X+(aq)+OHX−(aq)\ce{NH3(aq) + H2O(l) <=> NH4+(aq) + OH-(aq)}

Ammonia is the base (it accepts a proton, using the lone pair on nitrogen) and water is the acid (it donates a proton). The hydroxide ions formed make the solution alkaline.

So water can act as either an acid or a base, depending on what it reacts with. A substance that can do both is described as amphoteric (or, for proton transfer specifically, amphiprotic).

Conjugate acid–base pairs

Every Brønsted–Lowry reaction is a proton transfer, and it is reversible in principle. When an acid donates a proton, what remains can accept one back: it is a base. These two species form a conjugate acid–base pair, differing by one HX+\ce{H+}.

CHX3COOH+HX2O⇌CHX3COOX−+HX3OX+\ce{CH3COOH + H2O <=> CH3COO- + H3O+}
CHX3COOH\ce{CH3COOH}HX2O\ce{H2O}CHX3COOX−\ce{CH3COO-}HX3OX+\ce{H3O+}
acid 1base 2base 1acid 2
  • CHX3COOH\ce{CH3COOH} and CHX3COOX−\ce{CH3COO-} are a conjugate pair (acid 1 and its conjugate base).
  • HX2O\ce{H2O} and HX3OX+\ce{H3O+} are a conjugate pair (base 2 and its conjugate acid).
Method

Identifying conjugate pairs

  1. For each reactant, find the product that differs from it by exactly one HX+\ce{H+}.
  2. The member of each pair with the extra HX+\ce{H+} is the acid; the one without is the base.
  3. Check: each pair has one species on each side of the equation.

Strong and weak acids and bases

Definition

A strong acid (or strong base) is fully dissociated (ionised) in aqueous solution.

A weak acid (or weak base) is only partially dissociated in aqueous solution.

Hydrochloric acid is strong. Essentially every HCl molecule donates its proton:

HCl(aq)→HX+(aq)+ClX−(aq)\ce{HCl(aq) -> H+(aq) + Cl-(aq)}

Ethanoic acid is weak. In a 0.1 mol dm−30.1\ \text{mol dm}^{-3} solution only about one molecule in a hundred is dissociated at any moment; the rest remain as CHX3COOH\ce{CH3COOH} molecules. An equilibrium is set up that lies well to the left:

CHX3COOH(aq)⇌CHX3COOX−(aq)+HX+(aq)\ce{CH3COOH(aq) <=> CH3COO-(aq) + H+(aq)}

Similarly, sodium hydroxide is a strong base (fully dissociated into NaX+\ce{Na+} and OHX−\ce{OH-}), while ammonia is a weak base (only a small proportion reacts with water to form NHX4X+\ce{NH4+} and OHX−\ce{OH-}).

Watch out

Strong is not the same as concentrated. "Strong" and "weak" describe the extent of dissociation. "Concentrated" and "dilute" describe the amount of acid per volume of solution. You can have a dilute solution of a strong acid (0.001 mol dm−30.001\ \text{mol dm}^{-3} HCl) or a concentrated solution of a weak acid (glacial ethanoic acid).

Sulfuric acid is strong in its first dissociation, HX2SOX4→HX++HSOX4X−\ce{H2SO4 -> H+ + HSO4-}. At AS, treat it as a strong acid that can release two protons, giving sulfate salts with excess alkali.

The pH scale

The pH of a solution is a measure of its acidity: the higher the concentration of HX+(aq)\ce{H+(aq)}, the lower the pH.

Key result
  • Pure water has a pH of 7 (neutral) at 25 ∘C25\ ^\circ\text{C}.
  • Acidic solutions have a pH below 7.
  • Alkaline solutions have a pH above 7.
  • Each unit of pH corresponds to a tenfold change in [HX+][\ce{H+}].

pH can be measured with a pH meter (most precise) or estimated with universal indicator, which gives a range of colours from red (pH 1) through green (pH 7) to purple (pH 14).

Tip

At A Level you will calculate pH using pH=−log⁡10[HX+]\text{pH} = -\log_{10}[\ce{H+}]. At AS you only need to know the scale qualitatively and compare values.

Telling strong and weak acids apart

Compare 0.100 mol dm−30.100\ \text{mol dm}^{-3} hydrochloric acid and 0.100 mol dm−30.100\ \text{mol dm}^{-3} ethanoic acid. They have the same concentration of acid, but the strong acid has a much higher concentration of HX+\ce{H+} ions because it is fully dissociated.

testhydrochloric acid (strong)ethanoic acid (weak)reason
pH (pH meter)about 1about 3higher [HX+][\ce{H+}] in the strong acid
universal indicatorredorangehigher [HX+][\ce{H+}] in the strong acid
electrical conductivityhighlowmore ions in solution to carry the current
reaction with magnesium ribbonvigorous fizzing, magnesium dissolves quicklyslow fizzinghigher [HX+][\ce{H+}], so more frequent collisions with Mg
reaction with calcium carbonaterapid effervescenceslower effervescenceas above
total volume of HX2\ce{H2} from excess Mgsamesamethe same total moles of acid; as HX+\ce{H+} is used up, more ethanoic acid dissociates (equilibrium shifts right)
volume of NaOH to neutralisesamesamethe same moles of acid available to react

The last two rows are the trap. A weak acid reacts more slowly but not less: given time, every molecule of ethanoic acid can donate its proton, because removing HX+\ce{H+} shifts the dissociation equilibrium to the right.

Neutralisation and salts

In every reaction between an acid and an alkali in aqueous solution, the essential change is the same:

Key result
HX+(aq)+OHX−(aq)→HX2O(l)\ce{H+(aq) + OH-(aq) -> H2O(l)}

This is neutralisation. The other ions remain in solution as a salt.

A salt is the compound formed when the hydrogen of an acid is replaced by a metal ion or an ammonium ion. The acid determines the type of salt:

acidsaltexample
hydrochloric acidchlorideHCl+NaOH→NaCl+HX2O\ce{HCl + NaOH -> NaCl + H2O}
sulfuric acidsulfateHX2SOX4+2 KOH→KX2SOX4+2 HX2O\ce{H2SO4 + 2KOH -> K2SO4 + 2H2O}
nitric acidnitrateHNOX3+NHX3→NHX4NOX3\ce{HNO3 + NH3 -> NH4NO3}
ethanoic acidethanoateCHX3COOH+NaOH→CHX3COONa+HX2O\ce{CH3COOH + NaOH -> CH3COONa + H2O}

Other reactions of acids also form salts:

  • acid + metal oxide or hydroxide: salt + water, for example CuO+HX2SOX4→CuSOX4+HX2O\ce{CuO + H2SO4 -> CuSO4 + H2O};
  • acid + carbonate: salt + water + carbon dioxide, for example CaCOX3+2 HCl→CaClX2+HX2O+COX2\ce{CaCO3 + 2HCl -> CaCl2 + H2O + CO2};
  • acid + reactive metal: salt + hydrogen, for example Mg+2 HCl→MgClX2+HX2\ce{Mg + 2HCl -> MgCl2 + H2} (this is a redox reaction, not neutralisation);
  • acid + ammonia: an ammonium salt, with no water formed, for example NHX3+HCl→NHX4Cl\ce{NH3 + HCl -> NH4Cl}.

Worked examples

Routine: identifying Brønsted–Lowry acids and bases

In each reaction, identify the Brønsted–Lowry acid and base on the left-hand side.

(a) HNOX3+HX2O→HX3OX++NOX3X−\ce{HNO3 + H2O -> H3O+ + NO3-}

(b) NHX3+HCl→NHX4X++ClX−\ce{NH3 + HCl -> NH4+ + Cl-}

(c) COX3X2−+HX2O⇌HCOX3X−+OHX−\ce{CO3^2- + H2O <=> HCO3- + OH-}

Solution

(a) HNOX3\ce{HNO3} donates a proton: acid. HX2O\ce{H2O} accepts it: base.

(b) HCl\ce{HCl} donates a proton: acid. NHX3\ce{NH3} accepts it: base.

(c) HX2O\ce{H2O} donates a proton (becoming OHX−\ce{OH-}): acid. COX3X2−\ce{CO3^2-} accepts it (becoming HCOX3X−\ce{HCO3-}): base.

Conjugate pairs

Identify the two conjugate acid–base pairs in NHX3(aq)+HX2O(l)⇌NHX4X+(aq)+OHX−(aq)\ce{NH3(aq) + H2O(l) <=> NH4+(aq) + OH-(aq)}.

Solution

NHX3\ce{NH3} gains a proton to become NHX4X+\ce{NH4+}: NHX4X+\ce{NH4+} (acid) / NHX3\ce{NH3} (base) is one pair.

HX2O\ce{H2O} loses a proton to become OHX−\ce{OH-}: HX2O\ce{H2O} (acid) / OHX−\ce{OH-} (base) is the other pair.

Strong and weak acids

A student has two unlabelled solutions, each 0.10 mol dm−30.10\ \text{mol dm}^{-3}: one is hydrochloric acid and the other ethanoic acid. Describe two tests that would distinguish them, and explain the results.

Solution

Test 1: measure pH with a pH meter. Hydrochloric acid gives about pH 1, ethanoic acid about pH 3. HCl is fully dissociated, so [HX+][\ce{H+}] equals the acid concentration; ethanoic acid is only partially dissociated, so [HX+][\ce{H+}] is much lower and the pH higher.

Test 2: add equal lengths of magnesium ribbon. Hydrochloric acid fizzes much more vigorously. The higher [HX+][\ce{H+}] means more frequent collisions between HX+\ce{H+} ions and the magnesium surface.

(Measuring electrical conductivity also works: HCl conducts much better because it contains a higher concentration of ions.)

Same amount, different rate

25.0 cm325.0\ \text{cm}^3 samples of 0.100 mol dm−30.100\ \text{mol dm}^{-3} hydrochloric acid and 0.100 mol dm−30.100\ \text{mol dm}^{-3} ethanoic acid are each titrated with 0.100 mol dm−30.100\ \text{mol dm}^{-3} sodium hydroxide. Predict and explain the titres.

Solution

Both need 25.0 cm325.0\ \text{cm}^3 of sodium hydroxide.

Each sample contains 0.0250×0.100=2.50×10−3 mol0.0250 \times 0.100 = 2.50 \times 10^{-3}\ \text{mol} of acid, and each acid reacts with NaOH in a 1:11 : 1 ratio. For ethanoic acid, as OHX−\ce{OH-} removes the HX+\ce{H+} ions, the equilibrium CHX3COOH⇌CHX3COOX−+HX+\ce{CH3COOH <=> CH3COO- + H+} shifts to the right, so eventually all the ethanoic acid molecules react. The strength of an acid affects its pH and rate of reaction, not the amount of alkali it neutralises.

Exam-hard: an acid acting as a base

In the nitration of benzene, concentrated nitric acid is mixed with concentrated sulfuric acid. The first step is:

HX2SOX4+HNOX3⇌HSOX4X−+HX2NOX3X+\ce{H2SO4 + HNO3 <=> HSO4- + H2NO3+}

(a) Explain why nitric acid is acting as a base in this reaction. (b) Identify the conjugate acid–base pairs. (c) Suggest what this tells you about the relative strengths of sulfuric acid and nitric acid as acids.

Solution

(a) Nitric acid accepts a proton from sulfuric acid (becoming HX2NOX3X+\ce{H2NO3+}), so by the Brønsted–Lowry definition it is a base in this reaction. Whether a substance acts as an acid or a base depends on what it reacts with.

(b) HX2SOX4\ce{H2SO4} (acid) / HSOX4X−\ce{HSO4-} (conjugate base); HX2NOX3X+\ce{H2NO3+} (acid) / HNOX3\ce{HNO3} (conjugate base).

(c) Sulfuric acid donates a proton to nitric acid rather than the other way round, so sulfuric acid is the stronger acid (the better proton donor) of the two.

Watch out
  • Defining an acid as "a substance containing hydrogen". Methane contains hydrogen but is not an acid. Use "proton donor".
  • "A weak acid is a dilute acid." Weak means partially dissociated; dilute means low concentration.
  • "A weak acid neutralises less alkali." The same moles of acid neutralise the same moles of alkali, whatever the strength.
  • Writing a single arrow for a weak acid. Use ⇌\ce{<=>} for partial dissociation, →\ce{->} for full dissociation of a strong acid.
  • Conjugate pairs that differ by more than one proton, or that are on the same side of the equation.
Exam tip
  • Learn the definitions: Brønsted–Lowry acid, "proton donor"; base, "proton acceptor"; strong acid, "fully dissociated in aqueous solution"; weak acid, "partially dissociated".
  • "Explain the difference in pH" questions want: same concentration of acid; strong acid fully dissociated, weak acid partially; so [HX+][\ce{H+}] is higher in the strong acid; higher [HX+][\ce{H+}] means lower pH.
  • When writing the dissociation of a weak acid or weak base, include state symbols and the reversible arrow.
  • Questions on observations with magnesium or carbonates need observations (rate of bubbling, time for the solid to disappear) and an explanation in terms of [HX+][\ce{H+}] and collision frequency.
Summary
  • Common acids: HCl, HX2SOX4\ce{H2SO4}, HNOX3\ce{HNO3} (strong); CHX3COOH\ce{CH3COOH} (weak). Common alkalis: NaOH, KOH (strong); NHX3\ce{NH3} (weak).
  • Brønsted–Lowry acid: proton donor. Base: proton acceptor. Conjugate pairs differ by one HX+\ce{H+}.
  • Water is amphoteric: an acid towards NHX3\ce{NH3}, a base towards HCl.
  • Strong: fully dissociated in aqueous solution. Weak: partially dissociated (equilibrium).
  • pH 7 neutral, below 7 acidic, above 7 alkaline; lower pH means higher [HX+][\ce{H+}].
  • Same concentration: strong acid has lower pH, higher conductivity and reacts faster, but neutralises the same amount of alkali and gives the same total gas.
  • Neutralisation: HX+(aq)+OHX−(aq)→HX2O(l)\ce{H+(aq) + OH-(aq) -> H2O(l)}; the remaining ions form a salt.

Practice

Question
  1. Define a Brønsted–Lowry acid and a Brønsted–Lowry base.
  2. Write equations to show (a) nitric acid acting as an acid in water, (b) ammonia acting as a base in water.
  3. Identify the conjugate acid–base pairs in HCOX3X−+OHX−⇌COX3X2−+HX2O\ce{HCO3- + OH- <=> CO3^2- + H2O}.
  4. Explain, with equations, how the hydrogencarbonate ion, HCOX3X−\ce{HCO3-}, can act both as an acid and as a base.
  5. Explain the difference between a strong acid and a concentrated acid, giving an example of a dilute solution of a strong acid.
  6. Explain why 0.1 mol dm−30.1\ \text{mol dm}^{-3} ammonia solution has a lower pH than 0.1 mol dm−30.1\ \text{mol dm}^{-3} sodium hydroxide.
  7. Write balanced equations for the formation of (a) potassium sulfate from sulfuric acid and potassium hydroxide, (b) ammonium sulfate from ammonia and sulfuric acid, (c) sodium ethanoate from ethanoic acid and sodium carbonate.
  8. Equal masses of magnesium (in excess) are added to 50.0 cm350.0\ \text{cm}^3 of 1.0 mol dm−31.0\ \text{mol dm}^{-3} HCl and to 50.0 cm350.0\ \text{cm}^3 of 1.0 mol dm−31.0\ \text{mol dm}^{-3} CHX3COOH\ce{CH3COOH}. Compare (a) the initial rates of gas production and (b) the total volumes of hydrogen produced, explaining your answers. Calculate the volume of hydrogen at room conditions in each case.
  9. Hydrogen chloride dissolves in methylbenzene (a non-polar solvent) without forming ions, but in water it forms a strongly acidic solution. Use the Brønsted–Lowry theory to explain this difference.
  10. Pure liquid ammonia undergoes self-ionisation: 2 NHX3⇌NHX4X++NHX2X−\ce{2NH3 <=> NH4+ + NH2-}. By analogy with water, identify the acid and base species in liquid ammonia, and predict the products of the neutralisation reaction between ammonium chloride and sodium amide, NaNHX2\ce{NaNH2}, dissolved in liquid ammonia.
Answers
  1. Acid: proton donor. Base: proton acceptor.
  2. (a) HNOX3(aq)+HX2O(l)→HX3OX+(aq)+NOX3X−(aq)\ce{HNO3(aq) + H2O(l) -> H3O+(aq) + NO3-(aq)}. (b) NHX3(aq)+HX2O(l)⇌NHX4X+(aq)+OHX−(aq)\ce{NH3(aq) + H2O(l) <=> NH4+(aq) + OH-(aq)}.
  3. HCOX3X−\ce{HCO3-} (acid) / COX3X2−\ce{CO3^2-} (base); HX2O\ce{H2O} (acid) / OHX−\ce{OH-} (base).
  4. As an acid it donates a proton: HCOX3X−+OHX−→COX3X2−+HX2O\ce{HCO3- + OH- -> CO3^2- + H2O}. As a base it accepts a proton: HCOX3X−+HX+→HX2O+COX2\ce{HCO3- + H+ -> H2O + CO2} (via HX2COX3\ce{H2CO3}). It is amphoteric.
  5. A strong acid is fully dissociated in aqueous solution; a concentrated acid has a large amount of acid per unit volume. They describe different things. Example: 0.001 mol dm−30.001\ \text{mol dm}^{-3} hydrochloric acid is dilute but strong.
  6. Sodium hydroxide is a strong base, fully dissociated, so [OHX−]=0.1 mol dm−3[\ce{OH-}] = 0.1\ \text{mol dm}^{-3}. Ammonia is a weak base: only a small fraction reacts with water to form OHX−\ce{OH-}, so [OHX−][\ce{OH-}] is much lower and the solution is less alkaline (lower pH).
  7. (a) HX2SOX4+2 KOH→KX2SOX4+2 HX2O\ce{H2SO4 + 2KOH -> K2SO4 + 2H2O}. (b) 2 NHX3+HX2SOX4→(NHX4)X2SOX4\ce{2NH3 + H2SO4 -> (NH4)2SO4}. (c) 2 CHX3COOH+NaX2COX3→2 CHX3COONa+HX2O+COX2\ce{2CH3COOH + Na2CO3 -> 2CH3COONa + H2O + CO2}.
  8. (a) HCl gives a faster initial rate: it is fully dissociated, so [HX+][\ce{H+}] is higher and collisions between HX+\ce{H+} and Mg are more frequent. (b) The same total volume: each contains 0.0500 mol0.0500\ \text{mol} of acid; as HX+\ce{H+} is used up, more ethanoic acid dissociates until all has reacted. Mg+2 HX+→MgX2++HX2\ce{Mg + 2H+ -> Mg^2+ + H2}: n(HX2)=0.0250 moln(\ce{H2}) = 0.0250\ \text{mol}; volume =0.0250×24.0=0.600 dm3= 0.0250 \times 24.0 = 0.600\ \text{dm}^3 (600 cm3600\ \text{cm}^3) in each case.
  9. An acid can only donate a proton if there is a base to accept it. Methylbenzene has no lone pairs able to accept a proton, so HCl stays as molecules. Water is a base: a lone pair on oxygen accepts the proton, forming HX3OX+\ce{H3O+} and ClX−\ce{Cl-}, so the solution is acidic.
  10. In water, 2 HX2O⇌HX3OX++OHX−\ce{2H2O <=> H3O+ + OH-}: HX3OX+\ce{H3O+} is the acidic species and OHX−\ce{OH-} the basic species. By analogy, in liquid ammonia NHX4X+\ce{NH4+} is the acid (proton donor) and NHX2X−\ce{NH2-} the base (proton acceptor). Neutralisation: NHX4X++NHX2X−→2 NHX3\ce{NH4+ + NH2- -> 2NH3} (the solvent, like water in aqueous neutralisation). Overall: NHX4Cl+NaNHX2→NaCl+2 NHX3\ce{NH4Cl + NaNH2 -> NaCl + 2NH3}; the salt is sodium chloride.

How well do you know this?

Builds on

Where this leads

Console

Search notes, courses and tools, or run an action